2n^2+2n=2112

Solution for 2n^2+2n=2112 equation:

2n^2+2n=2112

We move all terms to the left:

2n^2+2n-(2112)=0

a = 2; b = 2; c = -2112;
Δ = b2-4ac
Δ = 22-4·2·(-2112)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-130}{2*2}=\frac{-132}{4}
=-33
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+130}{2*2}=\frac{128}{4}
=32
$